8x^2-8=64x

Solution for 8x^2-8=64x equation:

8x^2-8=64x

We move all terms to the left:

8x^2-8-(64x)=0

a = 8; b = -64; c = -8;
Δ = b2-4ac
Δ = -642-4·8·(-8)
Δ = 4352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4352}=\sqrt{256*17}=\sqrt{256}*\sqrt{17}=16\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-16\sqrt{17}}{2*8}=\frac{64-16\sqrt{17}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+16\sqrt{17}}{2*8}=\frac{64+16\sqrt{17}}{16}
$